Popis problému
Celý popis zadania sa nacháza – Hackerrank.
Riešenie
Vytvoril som riešenie v týchto programovacích jazykoch:
Všetky riešenia sú dostupné aj na mojom GitHub profile.
Ruby
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 |
class Move attr_reader :rolls, :position def initialize(position, rolls) @position = position @rolls = rolls end end test_cases = gets.chomp.to_i test_cases.times do (ladders_count, snakes_count) = gets.chomp.split(",").map { |e| e.to_i } ladders = gets.chomp.split snakes = gets.chomp.split ladders_hash = Hash.new snakes_hash = Hash.new ladders.each do |ladder| (start_p, end_p) = ladder.split(",").map { |e| e.to_i } ladders_hash[start_p] = end_p end snakes.each do |snake| (start_p, end_p) = snake.split(",").map { |e| e.to_i } snakes_hash[start_p] = end_p end start = Move.new(1, 0) moves = [] moves.push(start) rolls_at_hundred = [] while !moves.empty? do move = moves.shift actual_position = move.position actual_rolls = move.rolls if actual_position >= 100 rolls_at_hundred << actual_rolls next end for i in 1..5 pos = ladders_hash[actual_position + i] if !pos.nil? new_move = Move.new(pos, actual_rolls + 1) moves.push(new_move) end end pos = ladders_hash[actual_position + 6] if pos.nil? without_ladder = Move.new(actual_position + 6, actual_rolls + 1) moves.push(without_ladder) else new_move = Move.new(pos, actual_rolls + 1) moves.push(new_move) end end rolls_at_hundred.sort! { |k, l| k <=> l} puts rolls_at_hundred[0] end |