Archives sum - Pavol Pidanič

Hackerrank – Handshake

Problem Statement A description of the problem can be found on Hackerrank. Solution I created solution in: Java JavaScript Ruby Scala All solutions are also available on my GitHub. Java

import java.util.*;

public class Handshake {

    public static void main(String[] args) {
        Scanner stdin = new Scanner(System.in);
        int tests = stdin.nextInt();
        for(int i = 0; i < tests; i++) {
            long handshakes = 0;
            int directors = stdin.nextInt();
            for(int j = 0; j < directors; j++) {
                handshakes += j;
            }
            System.out.println(handshakes);
        }
        stdin.close();
    }
}

import java.util.*;

public class Handshake {

public static void main(String[] args) {

Scanner stdin = new Scanner(System.in);

int tests = stdin.nextInt();

for(int i = 0; i < tests; i++) {

long handshakes = 0;

int directors = stdin.nextInt();

for(int j = 0; j < directors; j++) {

handshakes += j;

}

System.out.println(handshakes);

}

stdin.close();

}

JavaScript

'use strict';

const processData = input => {
    let directors = input.split('\n').map(i => parseInt(i))
    for(let i = 1; i < directors.length; i++) {
        let handshakes = 0;
        for(let j = 0; j < directors[i]; j++) {
            handshakes += j;
        }
        console.log(handshakes);
    }
};

process.stdin.resume();
process.stdin.setEncoding("ascii");

var _input = "";
process.stdin.on("data", input => _input += input);
process.stdin.on("end", () => processData(_input));

'use strict';

const processData = input => {

let directors = input.split('\n').map(i => parseInt(i))

for(let i = 1; i < directors.length; i++) {

let handshakes = 0;

for(let j = 0; j < directors[i]; j++) {

handshakes += j;

}

console.log(handshakes);

}

};

process.stdin.resume();

process.stdin.setEncoding("ascii");

var _input = "";

process.stdin.on("data", input => _input += input);

process.stdin.on("end", () => processData(_input));

Ruby

gets.chomp.to_i.times do
  directors = gets.chomp.to_i
  result = 0
  (directors - 1).downto 0 do |handshakes|
    result += handshakes
  end
  puts result
end

gets.chomp.to_i.times do

directors = gets.chomp.to_i

result = 0

(directors - 1).downto 0 do |handshakes|

result += handshakes

end

puts result

end

Scala

import scala.io.Source

object Handshake extends App {
  val lines = Source.stdin.getLines()
  val directors = lines.drop(1).map(_.toInt)
  val handshakes = directors.map(Range(0, _).toList.sum)
  println(handshakes.mkString("\n"))
}

import scala.io.Source

object Handshake extends App {

val lines = Source.stdin.getLines()

val directors = lines.drop(1).map(_.toInt)

val handshakes = directors.map(Range(0, _).toList.sum)

println(handshakes.mkString("\n"))

}

Problem Statement A description of the problem can be found on Hackerrank. Solution Read from input and sum all numbers. Same as Simple Array Sum, but you have to use bigger integer type as 32-bit integer if language does not support automatic conversion to Big Integers as default I created solution in 4 languages: Scala […]

Hackerrank – Simple Array Sum

Problem Statement A description of the problem can be found on Hackerrank. Solution As this challenge is in Warmup subdomain, solution is pretty easy. The only thing to do is to be able to read from input given n times and make sum of all numbers. I created solution in 4 languages: Scala Java JavaScript […]

Pavol Pidanič

I can count to 1023 with 10 fingers

Tag: sum

Hackerrank – Handshake

Hackerrank – A Very Big Sum

Hackerrank – Simple Array Sum