Hackerrank - Find Digits - Pavol Pidanič

Problem Statement
A description of the problem can be found on Hackerrank.

Solution
Count all digits if the digit is greatest than 0 and if the input is divisible by digit.

I created solution in:

Java
JavaScript
Scala
Ruby

All solutions are also available on my GitHub.

Java

import java.util.Scanner;

public class FindDigits 
{
    public static void main(String[] args)
    {
        Scanner stdin = new Scanner(System.in);
        int tests = Integer.parseInt(stdin.nextLine());
        for(int i = 0; i < tests; i++)
        {
            int result = 0;
            String number = stdin.nextLine();
            for(char digit : number.toCharArray())
            {
                if(Character.getNumericValue(digit) != 0 
                        && Integer.parseInt(number) % Character.getNumericValue(digit) == 0)
                {
                    result++;
                }
            }
            System.out.println(result);
        }
        stdin.close();
    }
}

import java.util.Scanner;

public class FindDigits

{

public static void main(String[] args)

{

Scanner stdin = new Scanner(System.in);

int tests = Integer.parseInt(stdin.nextLine());

for(int i = 0; i < tests; i++)

{

int result = 0;

String number = stdin.nextLine();

for(char digit : number.toCharArray())

{

if(Character.getNumericValue(digit) != 0

&& Integer.parseInt(number) % Character.getNumericValue(digit) == 0)

{

result++;

}

System.out.println(result);

}

stdin.close();

}

JavaScript

function processData(input) {
    var inputs = input.split('\n');
    var tests = parseInt(inputs[0]);

    for(var i = 0; i < tests; i++) {
        for(var j = 1; j < inputs.length; j++) {
            var result = 0;
            var num = parseInt(inputs[j]);
            for(var k = 0; k < inputs[j].length; k++) {
                var c = parseInt(inputs[j][k]);
                if(c > 0 && num % c === 0) {
                    result++;
                }
            }
            console.log(result);
        }
        return;
    }
}

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
    processData(_input);
});

function processData(input) {

var inputs = input.split('\n');

var tests = parseInt(inputs[0]);

for(var i = 0; i < tests; i++) {

for(var j = 1; j < inputs.length; j++) {

var result = 0;

var num = parseInt(inputs[j]);

for(var k = 0; k < inputs[j].length; k++) {

var c = parseInt(inputs[j][k]);

if(c > 0 && num % c === 0) {

result++;

}

console.log(result);

}

return;

}

process.stdin.resume();

process.stdin.setEncoding("ascii");

_input = "";

process.stdin.on("data", function (input) {

_input += input;

});

process.stdin.on("end", function () {

processData(_input);

});

Scala

object FindDigits extends App {
  var inputs = io.Source.stdin.getLines().toList.tail

  inputs.foreach {
    in =>
      println(in.toCharArray.count(d =>
        d.getNumericValue != 0 && in.toInt % d.getNumericValue == 0))
  }
}

object FindDigits extends App {

var inputs = io.Source.stdin.getLines().toList.tail

inputs.foreach {

in =>

println(in.toCharArray.count(d =>

d.getNumericValue != 0 && in.toInt % d.getNumericValue == 0))

}

Ruby

t = gets.to_i
t.times do
  num = gets.chomp.to_s
  result = 0
  num.split("").each do |c|
    c_num = c.to_i
    result +=1 if c_num > 0 && num.to_i % c_num == 0
  end
  puts result
end

t = gets.to_i

t.times do

num = gets.chomp.to_s

result = 0

num.split("").each do |c|

c_num = c.to_i

result +=1 if c_num > 0 && num.to_i % c_num == 0

end

puts result

end

Pavol Pidanič

I can count to 1023 with 10 fingers

Hackerrank – Find Digits