Hackerrank - The British and American Style of Spelling

Problem Statement
A description of the problem can be found on Hackerrank.

Solution
For each word in each sentence check if the word contains "ze" (US) or "se" (UK).

I created solution in:

Scala
Ruby
JavaScript
Java

All solutions are also available on my GitHub.

Scala

import scala.io.Source

object AmericanEnglishSpelling extends App {
  val lines = Source.stdin.getLines().toList
  val n = lines(0).toInt
  val words = lines.slice(1, n + 1).map(_.split(" ")).flatten
  val tests = lines(n + 1).toInt
  val testWords = lines.drop(n + 2)
  val counts = testWords.map(w => words.count(isUsOrUkSpelling(_, w)))
  println(counts.mkString("\n"))

  def isUsOrUkSpelling(word: String, matching: String): Boolean = {
    word.matches(matching) || word.matches(matching.replaceAll("ze", "se"))
  }
}

import scala.io.Source

object AmericanEnglishSpelling extends App {

val lines = Source.stdin.getLines().toList

val n = lines(0).toInt

val words = lines.slice(1, n + 1).map(_.split(" ")).flatten

val tests = lines(n + 1).toInt

val testWords = lines.drop(n + 2)

val counts = testWords.map(w => words.count(isUsOrUkSpelling(_, w)))

println(counts.mkString("\n"))

def isUsOrUkSpelling(word: String, matching: String): Boolean = {

word.matches(matching) || word.matches(matching.replaceAll("ze", "se"))

}

Ruby

lines = gets.chomp.to_i
all_words = []
lines.times do
  words = gets.chomp.split.map { |s| s.to_s }
  words.each { |w| all_words << w}
end

tests = gets.chomp.to_i
tests.times do
  us_word = gets.chomp.to_s
  uk_word = us_word.sub("ze", "se")
  count = 0
  all_words.each do |word|
    count += 1 if word == us_word || word == uk_word
  end
  puts count
end

lines = gets.chomp.to_i

all_words = []

lines.times do

words = gets.chomp.split.map { |s| s.to_s }

words.each { |w| all_words << w}

end

tests = gets.chomp.to_i

tests.times do

us_word = gets.chomp.to_s

uk_word = us_word.sub("ze", "se")

count = 0

all_words.each do |word|

count += 1 if word == us_word || word == uk_word

end

puts count

end

JavaScript

function processData(input) {
    var lines = input.split("\n");
    var n = parseInt(lines[0]);
    var words = [];
    for(var i = 1; i <= n; i++) {
        var arr = lines.split(" ");
        for(var j = 0; j < arr.length; j++) {
            words.push(arr[j]);
        }
    }
    var tests = parseInt(lines[n + 1]);
    for(var t = n + 1; t <= n + tests; t++) {
        var count = 0;
        var american = lines[t];
        var british = lines[t].replace(/ze/g, "se");
        for(var w = 0; w < words.length; w++) {
            if(w.match(american) || w.match(british)) {
                count++;
            }
        }
        console.log(count);
    }
}

process.stdin.resume();
process.stdin.setEncoding("ascii");
_input = "";
process.stdin.on("data", function (input) {
    _input += input;
});

process.stdin.on("end", function () {
    processData(_input);
});

function processData(input) {

var lines = input.split("\n");

var n = parseInt(lines[0]);

var words = [];

for(var i = 1; i <= n; i++) {

var arr = lines.split(" ");

for(var j = 0; j < arr.length; j++) {

words.push(arr[j]);

}

var tests = parseInt(lines[n + 1]);

for(var t = n + 1; t <= n + tests; t++) {

var count = 0;

var american = lines[t];

var british = lines[t].replace(/ze/g, "se");

for(var w = 0; w < words.length; w++) {

if(w.match(american) || w.match(british)) {

count++;

}

console.log(count);

}

process.stdin.resume();

process.stdin.setEncoding("ascii");

_input = "";

process.stdin.on("data", function (input) {

_input += input;

});

process.stdin.on("end", function () {

processData(_input);

});

Java

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;

public class BritishAndAmericanSpelling {
    public static void main(String[] args) {
        Scanner stdin = new Scanner(System.in);
        int n = Integer.parseInt(stdin.nextLine());
        List<String> words = new ArrayList<>();
        for(int i = 0; i < n; i++) {
            String[] s = stdin.nextLine().split(" ");
            words.addAll(Arrays.asList(s));
        }
        int tests = Integer.parseInt(stdin.nextLine());
        for(int i = 0; i < tests; i++) {
            int count = 0;
            String american = stdin.nextLine();
            String british = american.replaceAll("ze", "se");
            for(int j = 0; j < words.size(); j++) {
                if(words.get(j).matches(american) || words.get(j).matches(british)) {
                    count++;
                }
            }
            System.out.println(count);
        }

        stdin.close();
    }
}

import java.util.ArrayList;

import java.util.Arrays;

import java.util.List;

import java.util.Scanner;

public class BritishAndAmericanSpelling {

public static void main(String[] args) {

Scanner stdin = new Scanner(System.in);

int n = Integer.parseInt(stdin.nextLine());

List<String> words = new ArrayList<>();

for(int i = 0; i < n; i++) {

String[] s = stdin.nextLine().split(" ");

words.addAll(Arrays.asList(s));

}

int tests = Integer.parseInt(stdin.nextLine());

for(int i = 0; i < tests; i++) {

int count = 0;

String american = stdin.nextLine();

String british = american.replaceAll("ze", "se");

for(int j = 0; j < words.size(); j++) {

if(words.get(j).matches(american) || words.get(j).matches(british)) {

count++;

}

System.out.println(count);

}

stdin.close();

}

Pavol Pidanič

I can count to 1023 with 10 fingers

Hackerrank – The British and American Style of Spelling