Hackerrank - Java If-Else - Pavol Pidanič

Problem Statement
A description of the problem can be found on Hackerrank.

Solution

I created solution in:

Java

All solutions are also available on my GitHub.

Java

import java.util.*;

public class JavaIfElse {
   public static void main(String[] args) {
       Scanner sc = new Scanner(System.in);
       int n = sc.nextInt();            
       String ans = "";
       if(n % 2 == 1) {
           ans = "Weird";
       }
       else {
           if(n >= 2 && n <= 5) {
               ans = "Not Weird";
           } else if(n >= 6 && n <= 20) {
               ans = "Weird";
           } else {
               ans = "Not Weird";
           }
       }
       System.out.println(ans);
   }
}

import java.util.*;

public class JavaIfElse {

public static void main(String[] args) {

Scanner sc = new Scanner(System.in);

int n = sc.nextInt();

String ans = "";

if(n % 2 == 1) {

ans = "Weird";

}

else {

if(n >= 2 && n <= 5) {

ans = "Not Weird";

} else if(n >= 6 && n <= 20) {

ans = "Weird";

} else {

ans = "Not Weird";

}

System.out.println(ans);

}

Pavol Pidanič

I can count to 1023 with 10 fingers

Hackerrank – Java If-Else

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